From f654afde5d6bab13531d61e745b01e9edd57a81c Mon Sep 17 00:00:00 2001
From: "Hittner, Domonique (MAJ)" <domonique.hittner@nps.edu>
Date: Thu, 9 Sep 2021 10:41:25 -0700
Subject: [PATCH] Delete HittnerDTcpExampleServer.java
---
.../homework2/HittnerDTcpExampleServer.java | 88 -------------------
1 file changed, 88 deletions(-)
delete mode 100644 assignments/src/MV3500Cohort2021JulySeptember/homework2/HittnerDTcpExampleServer.java
diff --git a/assignments/src/MV3500Cohort2021JulySeptember/homework2/HittnerDTcpExampleServer.java b/assignments/src/MV3500Cohort2021JulySeptember/homework2/HittnerDTcpExampleServer.java
deleted file mode 100644
index becdc6e6bc..0000000000
--- a/assignments/src/MV3500Cohort2021JulySeptember/homework2/HittnerDTcpExampleServer.java
+++ /dev/null
@@ -1,88 +0,0 @@
-package MV3500Cohort2021JulySeptember.homework2.HittnerD;
-
-import java.io.*;
-import java.net.*;
-
-/**
- *
- * @author Dom Hittner
- */
-public class HittnerDTcpExampleServer {
-
- /**
- * Program invocation, execution starts here
- * If already compiled, can run using console in directory ../../build/classes/ by invoking \
- * java -classpath . TcpExamples.TcpExample3Server
- * @param args command-line arguments
- */
- public static void main(String[] args) {
- try {
-
- // ServerSocket waits for a connection from a client.
- // Notice that it is outside the loop; ServerSocket
- // needs to be made only once.
- System.out.println(HittnerDTcpExampleServer.class.getName() + " has started..."); // it helps debugging to put this on console first
-
- ServerSocket serverSocket = new ServerSocket(2317);
- OutputStream os;
- PrintStream ps;
- InetAddress localAddress, remoteAddress;
- int localPort, remotePort;
- int serverLoopCount = 0;
-
- // Server is up and waiting (i.e. "blocked" or paused)
- // Loop, infinitely, waiting for client connections.
- // Stop the program somewhere else.
- while (true) {
-
- // block until connected to a client
- try (Socket clientConnectionSocket = serverSocket.accept())
- {
- serverLoopCount++; // increment at beginning of loop for reliability
-
- // Now hook everything up (i.e. set up the streams), Java style:
- os = clientConnectionSocket.getOutputStream();
- ps = new PrintStream(os);
- ps.println("okay " + serverLoopCount + " let's go to Starbucks"); // this gets sent back to client!
-
- // Print some information locally about the Socket connection.
- // This includes the port and IP numbers on both sides (the socket pair).
- localAddress = clientConnectionSocket.getLocalAddress();
- remoteAddress = clientConnectionSocket.getInetAddress();
- localPort = clientConnectionSocket.getLocalPort();
- remotePort = clientConnectionSocket.getPort();
-
- System.out.print ("Server loop " + serverLoopCount + ": ");
-
- // My socket pair connection looks like this, to localhost:
- // Socket pair: (( /0:0:0:0:0:0:0:1, 2317 ), ( /0:0:0:0:0:0:0:1, 54876 ))
- // Socket pair: (( /0:0:0:0:0:0:0:1, 2317 ), ( /0:0:0:0:0:0:0:1, 54881 ))
-
- // Why is the first IP/port the same, while the second set has different ports?
- System.out.println(HittnerDTcpExampleServer.class.getName() + " socket pair showing host name, address, port:");
- System.out.println(" (( " +
- localAddress.getHostName() + "=" + localAddress.getHostAddress() + ", " + localPort + " ), ( " +
- remoteAddress.getHostName() + "=" + remoteAddress.getHostAddress() + ", " + remotePort + " ))");
-
- if ( localAddress.getHostName().equals( localAddress.getHostAddress()) ||
- remoteAddress.getHostName().equals(remoteAddress.getHostAddress()))
- System.out.println(" note HostName matches address if host has no DNS name");
-
- // Notice the use of flush() and try w/ resources. Without
- // the try w/ resources the Socket object may stay open for
- // a while after the client has stopped needing this
- // connection. try w/ resources explicitly ends the connection.
- ps.flush();
- // like it or not, you're outta here!
- }
- }
- } catch (IOException e) {
- System.err.println("Problem with " + HittnerDTcpExampleServer.class.getName() + " networking: " + e);
-
- // Provide more helpful information to user if exception occurs due to running twice at one time
- if (e instanceof java.net.BindException) {
- System.err.println("*** Be sure to stop any other running instances of programs using this port!");
- }
- }
- }
-}
--
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